Don't Miss a Chance to Chat With Experts. It's Free!

Hw Answer Operation Management Heizer Ch 4

4.9 [pic] (c)? MAD (two-month moving average) = .075 MAD (three-month moving average) = .

Stop Using Plagiarized Content. Get a 100% Unique Essay on Hw Answer Operation Management Heizer Ch 4

for $13,9/Page.

Get Essay

088 |Table for Problem 4. (a, b, c) | | | | |Forecast | ||Error| | | | |Two-Month |Three-Month |Two-Month |Three-Month | | |Price per |Moving |Moving |Moving |Moving | |Month |Chip |Average |Average |Average |Average | |January |$1. 0 | | | | | |February |? 1. 67 | | | | | |March |? 1. 70 |1. 735 | |. 035 | | |April |? 1. 85 |1. 685 |1. 723 |. 165 |. 127 | |May |? 1. 90 |1. 775 |1. 740 |. 125 |. 160 | |June |? 1. 87 |1. 75 |1. 817 |. 005 |. 053 | |July |? 1. 80 |1. 885 |1. 873 |. 085 |. 073 | |August |? 1. 83 |1. 835 |1. 857 |. 005 |. 027 | |September |? 1. 70 |1. 815 |1. 833 |. 115 |. 133 | |October |? 1. 65 |1. 765 |1. 777 |. 115 |. 127 | |November |? 1. 70 |1. 675 |1. 27 |. 025 |. 027 | |December |? 1. 75 |1. 675 |1. 683 |. 075 |. 067 | | | | |Totals |. 750| |. 793| | | | | | | | | | | |4. 9 |(d)? Table for Problem 4. 9(d): | | | | |( = . 1 | | |( = . 3 | | |( = . | |Month |Price per Chip |Forecast ||Error| |Forecast ||Error| |Forecast ||Error| | |January |$1. 80 |$1. 80 |$. 00 |$1. 80 |$. 00 |$1. 80 |$. 00 | |February |1. 67 |1. 80 |. 13 |? 1. 80 | . 13 |? 1. 80 |. 13 | |March |1. 70 |1. 79 |. 09 |? 1. 76 | . 06 |? 1. 74 |. 04 | |April |1. 85 |1. 78 |. 07 |? 1. 74 | . 11 |? 1. 72 |. 13 | |May |1. 0 |1. 79 |. 11 |? 1. 77 | . 13 |? 1. 78 |. 12 | |June |1. 87 |1. 80 |. 07 |? 1. 81 | . 06 |? 1. 84 |. 03 | |July |1. 80 |1. 80 |. 00 |? 1. 83 | . 03 |? 1. 86 |. 06 | |August |1. 83 |1. 80 |. 03 |? 1. 82 | . 01 |? 1. 83 |. 00 | |September |1. 70 |1. 81 |. 11 |? 1. 82 | . 12 |? 1. 83 |. 13 | |October |1. 65 |1. 80 |. 5 |? 1. 79 | . 14 |? 1. 76 |. 11 | |November |1. 70 |1. 78 |. 08 |? 1. 75 | . 05 |? 1. 71 |. 01 | |December |1. 75 |1. 77 |. 02 |? 1. 73 | . 02 |? 1. 70 |. 05 | | | | | 4. 41? (a)? It appears from the following graph that the points do scatter around a straight line. [pic] (b)? Developing the regression relationship, we have: (Summer |Tourists |Ridership | | | | |months) |(Millions) |(1,000,000s) | | | | |Year |(X) |(Y) |X2 |Y2 |XY | |? 1 |? 7 |1. 5 |? 49 |? 2. 25 |10. 5 | |? 2 |? 2 |1. 0 |?? 4 |? 1. 00 |? 2. 0 | |? 3 |? 6 |1. 3 |? 36 |? 1. 69 |? 7. 8 | |? 4 |? 4 |1. 5 |? 16 |? 2. 25 |? 6. 0 | |? 5 |14 |2. 5 |196 |? 6. 25 |35. 0 | |? |15 |2. 7 |225 |? 7. 29 |40. 5 | |? 7 |16 |2. 4 |256 |? 5. 76 |38. 4 | |? 8 |12 |2. 0 |144 |? 4. 00 |24. 0 | |? 9 |14 |2. 7 |196 |? 7. 29 |37. 8 | |10 |20 |4. 4 |400 |19. 36 |88. 0 | |11 |15 |3. 4 |225 |11. 56 |51. 0 | |12 |? 7 |1. 7 |? 49 |? 2. 89 |11. 9 | and (X = 132, (Y = 27. 1, (XY = 352. 9, (X2 = 1796, (Y2 = 71. 59, [pic] = 11, [pic]= 2. 6. Then: [pic] andY = 0. 511 + 0. 159X (c)? Given a tourist population of 10,000,000, the model predicts a ridership of: Y = 0. 511 + 0. 159 ( 10 = 2. 101, or 2,101,000 persons. (d)? If there are no tourists at all, the model predicts a ridership of 0. 511, or 511,000 persons. One would not place much confidence in this forecast, however, because the number of tourists (zero) is outside the range of data used to develop the model. (e)? The standard error of the estimate is given by: (f)? The correlation coefficient and the coefficient of determination are given by: [pic] ———————– [pic][pic]

How to cite Hw Answer Operation Management Heizer Ch 4, Essays

Choose cite format:
Hw Answer Operation Management Heizer Ch 4. (2016, Dec 19). Retrieved March 31, 2020, from https://phdessay.com/hw-answer-operation-management-heizer-ch-4-177697/.